Hiiiii I need help with Pythagorean Math here is a picture of the answer I REALLY NEED! this was due like monday- and lol I didn't turn it in cause I was busy with benchmark, Anywhoooo can someone pleaseee help me.... Please dont take my points :(((

Answer:
Hypotenuse of first triangle is 7.61
Hypotenuse of second triangle is 45
Step-by-step explanation:
Given that:
Triangle 1:
a = 3
b = 7
Using Pythagorean theorem;
a²+b²=c²
[tex](3)^2+(7)^2=c^2\\9+49=c^2\\c^2=58[/tex]
Taking square root on both sides
[tex]\sqrt{c^2}=\sqrt{58}\\[/tex]
c = 7.61
Hypotenuse is 7.61
Triangle 2:
a = 27
b = 36
Using Pythagorean theorem;
a²+b²=c²
[tex](27)^2+(36)^2= c^2\\729+1296=c^2\\c^2=2025[/tex]
Taking square root on both sides
[tex]\sqrt{c^2}=\sqrt{2025}\\[/tex]
c=45
Hypotenuse is 45
Hence,
Hypotenuse of first triangle is 7.61
Hypotenuse of second triangle is 45