On a coordinate plane, 2 exponential functions are shown. f (x) = 5 Superscript x Baseline approaches y = 0 in quadrant 2 and increases in quadrant 1. It goes though (0, 1) and (1, 5). g (x) = 5 Superscript x Baseline + k approaches y = negative 7.5 in quadrant 3 and increases into quadrant 4 going through (0, negative 6) and (1, negative 2).
The graph of f(x) was vertically translated down by a value of k to get the function g(x) = 5x + k. What is the value of k?

−7
−6
5
7

Respuesta :

Answer:

[tex]k = -7[/tex]

Explanation:

Given

[tex]f(x) = 5^x[/tex] through (0,1) and (1,5)

[tex]g(x) = 5^x + k[/tex] through (0,-6) and (1,-2)

Required

Determine the value of k if f(x) is translated vertically down

To get the value of k, we perform the following operations.

For (0,-6) --- Substitute 0 for x and -6 for g(x) in [tex]g(x) = 5^x + k[/tex]

[tex]g(x) = 5^x + k[/tex]

[tex]-6 = 5^0 + k[/tex]

[tex]-6 = 1 + k[/tex]

[tex]k + 1 = -6[/tex]

[tex]k = -6 - 1[/tex]

[tex]k = -7[/tex]

For (1,-2) --- Substitute 1 for x and -2 for g(x) in [tex]g(x) = 5^x + k[/tex]

[tex]g(x) = 5^x + k[/tex]

[tex]-2 = 5^1 + k[/tex]

[tex]-2 = 5 + k[/tex]

[tex]k+5 = -2[/tex]

[tex]k= -2-5[/tex]

[tex]k = -7[/tex]

To further show that k = -7, we have the following:

[tex]f(x) = 5^x[/tex]

When translated downward by 7 units, the function becomes

[tex]g(x) = f(x) - 7[/tex]

Recall that: [tex]g(x) = 5^x + k[/tex] and [tex]f(x) = 5^x[/tex]

So, we have:

[tex]5^x + k = 5^x - 7[/tex]

Subtract [tex]5^x[/tex] from both sides

[tex]5^x - 5^x + k = 5^x - 5^x + 7[/tex]

[tex]k = -7[/tex]

Answer:

(A) -7

Explanation: