Solve for x.
(2x + 43)°
(2x - 3)

Angles within the transversal of parallel lines add up to 180, so, the value of x is 35.
Given
[tex]\angle 1 = 2x + 43[/tex]
[tex]\angle 2 = 2x -3[/tex]
Both angles are interior angles of a transversal.
So:
[tex]\angle 1 + \angle 2 =180[/tex]
This gives
[tex]2x + 43 + 2x - 3 = 180[/tex]
Collect like terms
[tex]2x + 2x = 180 +3 - 43[/tex]
[tex]4x = 140[/tex]
Divide both sides by 4
[tex]x = 35[/tex]
Hence, the value of x is 35.
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