Answer:
t = 0.18 s
Explanation:
Given that,
The mas of a golf ball, m = 0.09 kg
It hits the ground with a speed of 80.90 m/s and with a force of 39.38 N.
We need to find the time of contact of the club with the ball.
The net force is given by :
[tex]F=\dfrac{m(v-u)}{t}\\\\t=\dfrac{m(v-u)}{F}\\\\t=\dfrac{0.09\times 80.9}{39.38 }\\\\=0.18\ s[/tex]
So, the time of contact is 0.18 s.
