Marie1969
contestada

in pushes a 500 N crate with an applied force of 1450 N to the left. He encounters a fridtional force of 200 N and his evil co-worker Jim adds a
500 N opposing force to the right. What is the magnitude and direction of the net force


A.1750 N. Right
B.2650 N Left
C. 750 N. left

Respuesta :

samuelonum1

Answer:

C. 750 N. left

Explanation:

let the force to the right be positive, and the left be negative

Step one:

given

mass of crate m= 500N

1450N force left

Frictional force of 200 N -----this opposes the motion

500 N opposing force to the right

The net force is equal to the summation of all the forces in Newton

Net force= -1450+200+500

Net force=-750N

The direction is right

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