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Question 4 (1 point) Lola and Keegan auditioned for the talent show. They decided to rap a new song. Keegan would sing every 8 seconds and Lola would sing every 14 seconds. If they sang together at the 2 minute and 10 second mark, when will they sing together again? They will sing together again at the min second mark.

Respuesta :

MrRoyal

Answer:

56th second

Step-by-step explanation:

Given

[tex]Lola = Every\ 8\ seconds[/tex]

[tex]Keegan = Every\ 14\ seconds[/tex]

[tex]Time = 2\ minutes\ 10\ seconds[/tex]

Required

Determine when they sing together

First, we convert the total time to seconds.

[tex]Time = 2\ minutes\ 10\ seconds[/tex]

[tex]Time = 2 * 60\ seconds + 10\ seconds[/tex]

[tex]Time = 120\ seconds + 10\ seconds[/tex]

[tex]Time = 130\ seconds[/tex]

Next, we determine the Least Common Multiple of Lola and Keegan's time:

Lola:

[tex]8\ seconds = 8, 16, 24, 32, 40, 48, 56, 64, 72, 80, 88, 96, 104, 112, 120, 128[/tex]

Keegan:

[tex]14\ seconds = 14, 28, 42, 56, 70, 84, 98, 112, 126[/tex]

The least common multiple is 56. Hence, they will sing together at the 56th second

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