Chris and Jamie are carrying Wayne on a horizontal stretcher. The uniform stretcher is 2.00 m long and weighs 100 N. Wayne weighs 800 N. Wayne's center of gravity is 75.0 cm from Chris. Chris and Jamie are at the ends of the stretcher. The upward force that Jamie is exerting to support the stretcher, with Wayne on it, is:______

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Complete Question

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Answer:

The value is [tex]F_j = 550\ N[/tex]

Explanation:

From the question we are told that

   The length of the stretcher is  [tex]d = 2.0 \ m[/tex]

    The weight of the stretcher is [tex]W = 100 \ N[/tex]

    The weight for Wayne is  [tex]W_w = 800 \ N[/tex]

     The distance of  center of gravity for Wayne from Chris is [tex]c_w = 75 cm = 0.75 \ m[/tex]

Generally taking moment about the first end where Chris is

         [tex]F_j * d[/tex]              => upward moment

Here [tex]F_j[/tex] is the force applied by Jamie

Generally  taking moment about the second end where Jamie is

      [tex]W * ( \frac{d}{2} ) + W_w * (d - c_w)[/tex]      => downward moment

Generally at equilibrium , the upward moment is equal to the downward moment

     [tex]F_j * d = W * ( \frac{d}{2} ) + W_w * (d - c_w)[/tex]

=>   [tex]F_j * 2 = 100 * ( \frac{ 2}{2} ) + 800 * (2 - 0.75)[/tex]

=>    [tex]F_j = 550\ N[/tex]

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