Answer:
21 rows 2 blocks
1 row 42 blocks
Step-by-step explanation:
Given that:
Number of blocks with Annabelle = 42
First arrangement = 3 rows 14 blocks
Second arrangement = 6 rows 7 blocks
To find:
The other two factor pairs that could be used to rearrange the blocks again?
Solution:
Here, we will have to find the factor pairs of total number of blocks present with Annabelle.
i.e. 42
First of all, let us have a look at the factor pairs of 42.
[tex]42 = 3\times 14\\42 = 6\times 7\\42 = \underline{2\times 21}\\42 = \underline{1\times 42}[/tex]
Therefore, the other two factor pairs can be 2, 21 and 1, 42.
The other two possible factor pairs are:
21 rows 2 blocks
1 row 42 blocks
Two other factors are 2 rows of 21 blocks and 1 row of 42 blocks.
Given that,
According to the scenario, computation of the given data are as follows,
Total factors for 42 blocks = 3 rows of 14 blocks , 6 rows of 7 blocks, 2 rows of 21 blocks and 1 row of 42 blocks.
As two of them are already used,
Then the other factors Annabelle could use = 2 rows of 21 blocks and 1 row of 42 blocks.
Learn more : brainly.com/question/11833462
