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In an all boys school, the heights of the student body are normally distributed with a
mean of 69 inches and a standard deviation of 2.5 inches. Using the empirical rule,
what percentage of the boys are between 61.5 and 76.5 inches tall?

Respuesta :

Answer:

99.7%

Step-by-step explanation:

99.7% of boys fall between 61.5 and 76.5

MrRoyal

The percentage of the boys that are between 61.5 and 76.5 inches tall is 99.73%

How to determine the percentage between the range?

The given parameters are:

  • Mean = 69
  • Standard deviation = 2.5

Start by calculating the z score for x = 61.5 and 76.5 using:

[tex]z = \frac{x - \mu}{\sigma}[/tex]

So, we have:

[tex]z_1 = \frac{61.5 - 69}{2.5} = -3[/tex]

[tex]z_2 = \frac{76.5 - 69}{2.5} = 3[/tex]

The percentage is then represented as:

Percentage = P(-3 < x < 3)

Using the z table of probabilities, we have:

Percentage = 0.9973


Express as percentage

Percentage = 99.73%

Hence, 99.73% of the boys are between 61.5 and 76.5 inches tall

Read more about normal distribution at:

https://brainly.com/question/4079902

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