Pls help its due in half an hour

Answer:
Common denominator 20
[tex] \frac{3}{ \: 4 \:} \: and \: \frac{2}{5} [/tex]
because 4 and 5 can both go into 20 without any remainder
Common denominator 18
[tex] \frac{3}{6} and \: \frac{2}{9} [/tex]
because 6 and 9 can both go into 18 without any remainder
Common denominator 8
[tex] \frac{1}{2} \: and \: \frac{7}{8} [/tex]
because 2 and 8 can both go into 8 without any remainder
Hope this was helpful!