Respuesta :

Oh wow mine is due in half an hour too

Answer:

Common denominator 20

[tex] \frac{3}{ \: 4 \:} \: and \: \frac{2}{5} [/tex]

because 4 and 5 can both go into 20 without any remainder

Common denominator 18

[tex] \frac{3}{6} and \: \frac{2}{9} [/tex]

because 6 and 9 can both go into 18 without any remainder

Common denominator 8

[tex] \frac{1}{2} \: and \: \frac{7}{8} [/tex]

because 2 and 8 can both go into 8 without any remainder

Hope this was helpful!