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2. (11 pts) Evaluate the following limits using the method of your choice. Show work to support your
answer. If the limit does not exist, state it clearly.
lim (x cos Tx + 2)
a.
Lim (2x-6)/(x^2-5x+6)
x-->3

Respuesta :

LammettHash

2x - 6 = 2 (x - 3)

and

x² - 5x + 6 = (x - 3) (x - 2)

so that

[tex]\displaystyle\lim_{x\to3}\frac{2x-6}{x^2-5x+6}=\lim_{x\to3}\frac2{x-2}=\boxed{2}[/tex]

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