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Find three consecutive integers such that twice the smallest is 12 more than the largest.

Show work!!!

Please anyone do this and put the right answer and show work I WILL MARK BRAINLIEST!!,

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Answer:

14, 15, 16

Step-by-step explanation:

Let integers equal:

x, x + 1, x + 2

2x = 12 + (x + 2)

2x = 12 + x + 2

2x = 14 + x

2x - x = 14

x = 14

x = 14

x + 1 = 14 + 1 = 15

x + 2 = 14 + 2 = 16

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