Answer:
[tex]\frac{x^{2} -8x+16}{x^{2} -7x+12}=\frac{x^{2} -2.4.x+4^{2} }{x^{2} -3x-4x+12}=\frac{(x-4)^{2} }{x(x-3)-4(x-3)}=\frac{(x-4)^{2} }{(x-4)(x-3)}=\frac{x-4}{x-3}[/tex]
Step-by-step explanation:
Answer:
(x-4)/(x-3)
Step-by-step explanation:
[tex] {x}^{2} - 4x + 16 = (x - 4)(x - 4)[/tex]
[tex] {x}^{2} - 7x + 12 = (x - 4)(x - 3)[/tex]
Therefore, on dividing, result is (x-4)/(x-3)
