Answer:
a) Factors of [tex]x^2-2x=x(x-2)[/tex]
b) Factors of [tex]6x^2+12x=6x(x+2)[/tex]
c) Factors of [tex]3x^3-9x=3x(x^2-3)[/tex]
d) Factors of [tex]4x^2+28x^3=4x^2(1-7x)[/tex]
Step-by-step explanation:
We need to factorise
a) [tex]x^2-2x[/tex]
Taking x common:
[tex]x^2-2x\\=x(x-2)[/tex]
So factors of [tex]x^2-2x=x(x-2)[/tex]
b) [tex]6x^2+12x[/tex]
Taking 6x common:
[tex]6x^2+12x\\=6x(x+2)[/tex]
So factors of [tex]6x^2+12x=6x(x+2)[/tex]
c) [tex]3x^3-9x[/tex]
Taking 3x common:
[tex]3x^3-9x\\=3x(x^2-3)[/tex]
So factors of [tex]3x^3-9x=3x(x^2-3)[/tex]
d) [tex]4x^2+28x^3[/tex]
Taking 4x common
[tex]4x^2+28x^3\\=4x^2(1+7x)[/tex]
So factors of [tex]4x^2+28x^3=4x^2(1-7x)[/tex]
