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What is the value of x^6+y^2x 6 +y 2 x, start superscript, 6, end superscript, plus, y, squared when x=1x=1x, equals, 1 and y=11y=11y, equals, 11?

Respuesta :

104788076

Try 122.

Step-by-step explanation:

Since x = 1, x^6 = 1.

Since y = 11, 11^2 = 121.

1 + 121 = 122.

So, the value of x ^ 6 + y ^ 2 = 122.

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