Answer:
We conclude that
[tex]4\frac{2}{3}[/tex] > [tex]\sqrt{21}[/tex]
Step-by-step explanation:
Given
as
[tex]\:\sqrt{21}=4.58[/tex]
and
[tex]4\frac{2}{3}[/tex]
Convert mixed numbers to improper fraction:
[tex]a\frac{b}{c}=\frac{a\cdot \:c+b}{c}[/tex]
so
[tex]4\frac{2}{3}=\frac{4\cdot 3+2}{3}=\frac{14}{3}=4.67[/tex]
Thus,
[tex]\:\sqrt{21}=4.58[/tex]
[tex]4\frac{2}{3}=4.67[/tex]
as
4.67 > 4.58
so
[tex]4\frac{2}{3}[/tex] > [tex]\sqrt{21}[/tex]
Hence, we conclude that
[tex]4\frac{2}{3}[/tex] > [tex]\sqrt{21}[/tex]
