Using proportions, it is found that the length of his drawing is of 4 mm.
The rule of three is:
1 mm - 2 in
x mm - 8 in
Applying cross multiplication:
[tex]2x = 8[/tex]
[tex]x = \frac{8}{2}[/tex]
[tex]x = 4[/tex]
The length of his drawing is of 4 mm.
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