Step-by-step explanation:
We need to find each of the following as a rational number in the form of p/q
(a) (3/7)² (b) (7/9)³ (c) (-2/3)⁴
Solution,
(a) (3/7)²
[tex](\dfrac{3}{7})^2=\dfrac{9}{49}[/tex]
(b) (7/9)³
[tex](\dfrac{7}{9})^3=\dfrac{7\times 7\times 7}{9\times 9\times 9}\\\\=\dfrac{343}{729}[/tex]
(c) (-2/3)⁴
[tex](\dfrac{-2}{3})^4=\dfrac{-2\times -2\times -2\times -2}{3\times 3\times 3\times 3}\\\\=\dfrac{16}{81}[/tex]
Hence, this is the required solution.
