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The gas in the discharge cell of a laser contains (in mole percent) 11% CO2, 5.3% N2, and 84% He. (a) What is the molar mass of this mixture

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sebassandin

Answer:

[tex]MM_{mixture}=9.68g/mol[/tex]

Explanation:

Hello!

In this case, since the molar mass of gaseous mixtures can be determined via a weighted average containing the molar mass of each gas and the mole fraction (mole percent divided by 100) as shown below:

[tex]MM_{mixture}=x_{CO_2}M_{CO_2}+x_{N_2}M_{N_2}+x_{He}M_{He}[/tex]

Now, we plug in to obtain:

[tex]MM_{mixture}=0.11*44g/mol+0.053*28+0.84*4\\\\MM_{mixture}=9.68g/mol[/tex]

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