Answer:
[tex]c=0.127\ J/g^{\circ} C[/tex]
Explanation:
Given that,
Mass of the sample, m = 275 g
It required 10.75 kJ of heat to change its temperature from 21.2 °C to its melting temperature, 327.5 °C.
We need to find the specific heat of the metal. The heat required by a metal sample is given by :
[tex]Q=mc\Delta T[/tex]
c is specific heat of the metal
[tex]c=\dfrac{Q}{m\Delta T}\\\\c=\dfrac{10.75\times 10^3\ J}{275\times (327.5 -21.2)}\\\\=0.127\ J/g^{\circ} C[/tex]
So, the specific heat of metal is [tex]0.127\ J/g^{\circ} C[/tex].
