Pounds of gold ore : 11,02311
Further explanation
Given
5 g of gold
0.1% gold by mass
Required
Pounds of gold ore
Solution
[tex]\tt \%mass~gold=\dfrac{mass~gold}{mass~ore}\times 100\%[/tex]
For percent mass = 0.1%, than mass of gold ore :
[tex]\tt 0.1\%=\dfrac{5~g}{mass~ore}\times 100\%\\\\mass~ore=\dfrac{5\times 100}{0.1}\\\\mass~ore=5000~g[/tex]
Conversion factor :
1 g = 0,00220462 pound, than for 5000 g = 11,02311 pounds
