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Answer:
[tex]molar \: mass \: of \: FeSO _{4}.7H _{2}0 = (56 + 32 + (16 \times 4) + (7 \times 18)) \\ = 278 \: g \\ \\ (278 \times 1000) \: mg \: of \: FeSO _{4}.7H _{2}0 \: contains \: (56 \times 1000) \: mg \: of \: Fe \\ 250 \: mg \: of \: FeSO _{4}.7H _{2}0 \: contain \: ( \frac{250 \times 56 \times 1000}{278 \times 1000} ) \\ = 50.35 \: mg \: of \: Fe[/tex]
The mass of Fe delivered by 250 mg Iron sulfate heptahydrate has been 50.35 mg.
The molar mass of the compound has been the sum of the mass of each element present in the compound. The given compound is iron sulfate heptahydrate. The compound has molar mass 278 grams.
1 mole of compound has been consisting of 1mole of iron.
278 grams Iron sulfate = 56 grams Fe
278,000 mg Iron sulfate = 56,000 mg Fe.
The mass of iron in 250 mg compound can be given as:
278,000 mg Iron sulfate = 56,000 mg Fe
[tex]\rm 250\;mg \;Iron\;sulfate\;=\;\dfrac{56,000}{278,000}\;\times\;250[/tex]
250 mg Iron sulfate tablet = 50.35 mg Fe.
The mass of Fe delivered by 250 mg Iron sulfate heptahydrate has been 50.35 mg.
For more information about the mass of compound, refer to the link:
https://brainly.com/question/2998100
