Respuesta :

okpalawalter8

Answer:

[tex]V_a =1.4285m/s[/tex]

Explanation:

From the question we are told that

70 kg astronaut

5 kg ball

A velocity of 20 m/s east

Generally with Law of conservation of momentum in place for a body in space

initial and final momentum must be equal

Therefore

[tex]M_b*V_b=M_a*V_a[/tex]

[tex]M_b=Mass of ball \\V_b=Ball velocity \\M_a= Mass of astronaut \\V_a= Astronaut velocity[/tex]

Mathematically solving for[tex]V_a[/tex]

[tex]V_a =\frac{5*20}{70}[/tex]

[tex]V_a =1.4285m/s[/tex]

Therefore the Astronauts velocity relative to his mass is given to be

[tex]V_a =1.4285m/s[/tex]

asuwafohjames

The velocity of the astronaut is 1.43 m/s.

From Newton's third law of motion,

To get the velocity of the astronaut, we use the formula below.

Formula:

  • MV = mv.................... Equation 1

Where:

  • M = mass of the astronaut
  • V = Velocity of the astronaut
  • m = mass of the ball
  • v = velocity of the ball.

make V the subject of the equation

  • V = mv/M................. Equation 2

From the question,

Given:

  • m = 5 kg
  • v = 20 m/s
  • M = 70 kg

Substitute these values into equation 2.

  • V = 5(20)/70
  • V = 1.43 m/s.

Hence, the velocity of the astronaut is 1.43 m/s.

Learn more about velocity here: https://brainly.com/question/6504879

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