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An air traffic controller is tracking two planes. To start, Plane A is at an altitude of 790 meters , and plane B was at an altitude of 1142 meters. Plane A losing altitude at 14 meters per second, and Plane B is losing altitude at 22 meters per second

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okpalawalter8

Answer:

[tex]x=4.375[/tex]

Step-by-step explanation

From the question we are told

Plane A starts at altitude 790

Plane B starts at altitude 1142

Plane A losing altitude at 14 meters per second

Plane B is losing altitude at 22 meters per second

Generally the altitude of both plane is given by

Plane A= [tex]790-14x[/tex]

Plane B=[tex]1142-22x[/tex]

Therefore when they exist in the same altitude

[tex]790-14x[/tex] =[tex]1142-22x[/tex]

[tex]-350=-8x[/tex]

[tex]\frac{-350}{-8} =x[/tex]

Therefore

[tex]x=4.375[/tex]

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