Answer:
Mass = 96 g
Explanation:
Given data:
Mass of oxygen required = ?
mass of Al = 110 g
Solution:
Chemical equation:
4Al + 3O₂ → 2Al₂O₃
Number of moles of Al:
Number of moles = mass/molar mass
Number of moles = 110 g/ 27 g/mol
Number of moles = 4 mol
Now we will compare the moles of Al and oxygen.
Al : O₂
4 : 3
Mass of oxygen:
Mass = number of moles × molar mass
Mass = 3 mol × 32 g/mol
Mass = 96 g
