Answer:
[tex]d=13.6\ lbs/in^3[/tex]
Explanation:
Given that,
Mass of a block, m = 82 lbs
Volume of the block, V = 6 inch³
We need to find the density of the block. Density of an object is equal to the mass per unit its volume. So,
[tex]d=\dfrac{m}{V}\\\\d=\dfrac{82\ lbs}{6\ in^3}\\\\=13.6\ lbs/in^3[/tex]
So, the required density is [tex]13.6\ lbs/in^3[/tex].
