Find the area of rectangle ABCD.
20
10 √2+ √82
24
12

Answer:
12 units²
Step-by-step explanation:
AB = [tex]\sqrt{(x_{2} -x_{1})^2 +(y_{2} -y_{1})^2 }[/tex] = [tex]\sqrt{(0-3)^2 +(0-3)^2}[/tex] = 3√2
BC = [tex]\sqrt{(5-3)^2 +(1-3)^2}[/tex] = 2√2
[tex]A_{ABCD}[/tex] = AB × BC = 3√2 × 2√2 = 12 units²
Answer:
So I did the assignment, and the answer that you're looking for in this problem would be 12.