The rate of change of distance between two cars at the given time is required.
The required rate of change is [tex]\sqrt{13}[/tex] feet/s
Rate of change
a = Distance covered in 5 s by bike A = [tex]2\times 5=10\ \text{feet}[/tex]
b = Distance covered in 5 s by bike B = [tex]3\times 5=15\ \text{feet}[/tex]
c = Distance between A and B in 5 s = [tex]\sqrt{10^2+15^2}=5\sqrt{13}\ \text{feet}[/tex]
Applying Pythagoras theorem
[tex]a^2+b^2=c^2[/tex]
Differentiating with respect to time
[tex]2a\dfrac{da}{dt}+2b\dfrac{db}{dt}=2c\dfrac{dc}{dt}\\\Rightarrow \dfrac{dc}{dt}=\dfrac{a\dfrac{da}{dt}+b\dfrac{db}{dt}}{c}\\\Rightarrow \dfrac{dc}{dt}=\dfrac{10\times 2+15\times 3}{5\sqrt{13}}\\\Rightarrow \dfrac{dc}{dt}=\sqrt{13}\ \text{feet/s}[/tex]
Learn more about rate of change:
https://brainly.com/question/8728504
