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Nora invested $6,300 in an account paying an interest rate of 7\tfrac{3}{4}7 4 3 ​ % compounded continuously. Ella invested $6,300 in an account paying an interest rate of 7\tfrac{1}{4}7 4 1 ​ % compounded monthly. After 11 years, how much more money would Nora have in her account than Ella, to the nearest dollar?

Respuesta :

Answer:

824

Step-by-step explanation:

DELTAMATH

The amount of money would Nora have more in her account than Ella after 11 years is $714 to the nearest dollar.

What is compound interest?

Compound interest is the amount charged on the principal amount and the accumulated interest with a fixed rate of interest for a time period.

The formula for the final amount with the compound interest formula can be given as,

[tex]A=P\times\left(1+\dfrac{r}{100}\right)^{t}\\[/tex]

Here, A is the final amount (principal plus interest amount) on the principal amount P of with the rate r of in the time period of t.

Nora invested $6,300 in an account paying an interest rate of 7(3/4)% compounded continuously. Convert this rate of interst in fractional form as,

[tex]r=7\dfrac{3}{4}\\r=\dfrac{31}{4}[/tex]

The principal amount of Nora is $6300 and time period is 11 years. Thus the amount in her account after 11 years will be,

[tex]A=6300\times\left(1+\dfrac{31}{4\times100}\right)^{11}\\A=14319.59[/tex]

Ella invested $6,300 in an account paying an interest rate of 7\tfrac{1}{4}7 4 1 ​ % compounded monthly.  Convert this rate of interst in fractional form as,

[tex]r=7\dfrac{1}{4}\\r=\dfrac{29}{4}[/tex]

The principal amount of Elia is $6300 and time period is 11 years. Thus the amount in her account after 11 years will be,

[tex]A=6300\times\left(1+\dfrac{29}{4\times100}\right)^{11}\\A=13605.39[/tex]

The differnce is,

[tex]d=14319.59-13605.39\\d=714.20\\d\approx714[/tex]

Thus the amount of money would Nora have more in her account than Ella after 11 years is $714 to the nearest dollar.

Learn more about the compound interest here;

https://brainly.com/question/24274034