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An applied force of 20 N accelerates a block across a level,frictionless surface from rest to a velocity of 8.0 m/s in a time of 2.5 s. Calculate the work done by this force.

Respuesta :

NusrathC

Answer:

workdone = force × distance

Explanation:

let's find the acceleration

[tex]v = u + at \\ 8 = 0 \times a \times 2.5 \\ \alpha = 3.2m {s}^{ - 2} [/tex]

then distance

[tex] {v}^{2} = {u}^{2} + 2as \\ {8}^{2} = 2 \times 3.2 \times s \\ \\ s = 10m [/tex]

w = f ×d

= 20 × 10

= 200J

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