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15 grams of hydrogen and 7.5 grams of oxygen were placed in a beaker. An explosion happened inside the baker that produced water. The beaker was never opened. How many grams of water were produced?

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maacastrobr

Answer:

16.8768 g

Explanation:

The reaction that takes place is:

  • 2H₂ + O₂ → 2H₂O

First we convert the mass of hydrogen and oxygen into moles, using their respective molar masses:

  • H ⇒ 15 g ÷ 1 g/mol = 15 mol H
  • O ⇒ 7.5 g ÷ 16 g/mol = 0.4688 mol O

There are significantly less oxygen moles than hydrogen moles, so oxygen is the limiting reactant.

We calculate the produced moles of water, using the moles of the limiting reactant:

  • 0.4688 mol O * [tex]\frac{2molH_2O}{1molO_2}[/tex] = 0.9376 mol H₂O

Finally we convert water moles into grams, using its molar mass:

  • 0.9376 mol H₂O * 18 g/mol = 16.8768 g

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