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Answer:
log₃(7) -2·log₃(5)
Step-by-step explanation:
The applicable rules of logarithms are ...
log(a/b) = log(a) -log(b)
log(a^b) = b·log(a)
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You have ...
[tex]\log_3\dfrac{7}{25}=\log_3{7}-\log_3{25}=\log_3{7}-\log_3{5^2}\\\\=\boxed{\log_3{7}-2\log_3{5}}[/tex]
