Respuesta :

dsdrajlin

Answer:

4.46 °C

Explanation:

Step 1: Given and required data

  • Energy absorbed (Q): 4430 J
  • Mass of water (m): 237 g
  • Specific heat of water (c): 4.186 J/g.°C

Step 2: Calculate the temperature change

We will use the following expression.

Q = c × m × ΔT

ΔT = Q / c × m

ΔT = 4430 J / (4.186 J/g.°C) × 237 g

ΔT = 4.46 °C

The temperature change is 4.46 °C.

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