Answer:
1.677 J/gºC
Explanation:
From the question given above, the following data were obtained:
Mass (M) = 23.9 g
Initial temperature (T₁) = 41.2 °C
Final temperature (T₂) = 68.9 °C
Heat (Q) absorbed = 1110 J
Specific heat capacity (C) of metal =?
Next, we shall determine the change in the temperature of the metal. This can be obtained as follow:
Initial temperature (T₁) = 41.2 °C
Final temperature (T₂) = 68.9 °C
Change in temperature (ΔT) =?
ΔT = T₂ – T₁
ΔT = 68.9 – 41.2
ΔT = 27.7 °C
Finally, we shall determine the specific heat capacity of the metal as follow:
Mass (M) = 23.9 g
Heat (Q) absorbed = 1110 J
Change in temperature (ΔT) = 27.7 °C
Specific heat capacity (C) of metal =?
Q = MCΔT
1110 = 23.9 × C × 27.7
1110 = 662.03 × C
Divide both side by 662.03
C = 1110 / 662.03
C = 1.677 J/gºC
Therefore, the specific heat capacity of the metal is 1.677 J/gºC
