anyone know the answer to number 11? there’s only 2 options and you can see them in the picture.

Answer:
Step-by-step explanation:
using S[tex]\frac{o}{h}[/tex] C[tex]\frac{a}{h}[/tex] T[tex]\frac{o}{a}[/tex] (sin opposite/hypotenuse, cos adjacent/hypotenuse, tan opposite/adjacent)
Tan Y = 3/8
Tan Z = 8/3
hope this helps <3