Given:
A certain function h(x) contains the point (8,-2).
To find:
The value of [tex]h^{-1}(-2)[/tex].
Solution:
If a function is defined as
[tex]f(x)=\{(a,b):a\in R,b\in R\}[/tex]
Then, its inverse is defined as
[tex]f^{-1}(x)=\{(b,a):a\in R,b\in R\}[/tex]
It is given that, a certain function h(x) contains the point (8,-2). It means, its inverse [tex]h^{-1}(x)[/tex] contains the point (-2,8). So, the value of inverse function is 8 at x=-2, i.e.,
[tex]h^{-1}(-2)=8[/tex]
Therefore, the value of [tex]h^{-1}(-2)[/tex] is 8.
