Answer:
[tex] \frac{ {(x - y)}^{2} }{2xy + 6y} \times \frac{4x + 12}{ {x}^{2} - {y}^{2} } \\ \frac{(x - y)(x - y)}{2y(x + 3)} \times \frac{4(x + 3)}{(x - y)(x + y)} \\ \frac{(x - y)}{y} \times \frac{2}{(x + y)} \\ \frac{2(x - y)}{y(x + y)} \\ \frac{(2x - 2y)}{(xy + {y}^{2}) } [/tex]
(2x-2y)/(xy+y^2) is the right answer.
