The amount of time T (in years) it will take for a population of a certain species to grow from 3500 to a can be modeled by the function Y(a)=log _(5) (a/3500)^1/0.03. Which function is equivalent?

Answer:
Option C is correct
Step-by-step explanation:
Here, we want to find which of the equations in the option is same as that in the question
The rule to use is that;
Loga B^y
= ylogaB
And also:
loga(X/Y) = logaX-logaY
Now, we start by applying these equations;
T(a) = log5 (a/3500)^1/0.03
T(a) = 1/0.03log5(a/3500)
T(a) = 1/0.03log5a - 1/0.03log53500
This makes the third option correct