The force applied in raising the block to the given height is 25 N.
The given parameters:
The force applied in raising the block to the given height is calculated as follows;
[tex]Work \ done= \ F \times d\\\\W = Fd\\\\F = \frac{W}{d} \\\\F = \frac{50 \ J}{2 \ m} \\\\F = 25 \ N[/tex]
Thus, the force applied in raising the block to the given height is 25 N.
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