Answer:
The cube of [tex](x+2)^3 \:is\:\mathbf{(x+2)(x^2-2x+4)}[/tex]
Step-by-step explanation:
We need to find cube of [tex](x+2)^3[/tex]
It can be found using formula: [tex](a+b)^3=(a+b)(a^2-ab+b^2)[/tex]
In the question given:
We have a = x and b = 2
Now finding cube using the above formula:
[tex](x+2)^3\\=(x+2)(x^2-(x)(2)+(2)^2)\\=(x+2)(x^2-2x+4)[/tex]
So, the cube of [tex](x+2)^3 \:is\:\mathbf{(x+2)(x^2-2x+4)}[/tex]
