Answer: [tex]45.21^{\circ }[/tex]
Step-by-step explanation:
Given
[tex]\angle J=90^{\circ }[/tex]
HI=88 ft
IJ=62 ft
From the figure, we can write
[tex]\cos I=\frac{IJ}{HI}=\frac{62}{88}=\frac{31}{44}\\I=\cos^{-1} (\frac{31}{44})=45.207^{\circ }\approx 45.21^{\circ }[/tex]