Answer: There are [tex]1.08 \times 10^{-14}[/tex] moles [tex]N_{2}O_{4}[/tex] present in [tex]6.49 \times 10^9[/tex] particles.
Explanation:
According to the mole concept, 1 mole of a substance contains [tex]6.022 \times 10^{23}[/tex] particles.
Hence, number of moles present in [tex]6.49 \times 10^9[/tex] particles are calculated as follows.
No. of moles = [tex]\frac{6.49 \times 10^9}{6.022 \times 10^{23}}[/tex] mol
= [tex]1.08 \times 10^{-14}[/tex] mol
Thus, there are [tex]1.08 \times 10^{-14}[/tex] moles [tex]N_{2}O_{4}[/tex] present in [tex]6.49 \times 10^9[/tex] particles.
Answer:
1.08 × 10⁻¹⁴ moles of N2O4
Explanation:
Given data:
Moles of dinitrogen tetroxide = ?
Number of particles = 6.49×10⁹
Solution:
Avogadro number:
The given problem will solve by using Avogadro number.
It is the number of atoms , ions , particles and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance. The number 6.022 × 10²³ is called Avogadro number.
1 mole contain 6.022 × 10²³ particles.
6.49×10⁹ particles × 1 mole / 6.022 × 10²³ particles
1.08 × 10⁻¹⁴ mol
