Answer:
Let the tens digit of the required number be x and the units digit be y. Then,
x+y=12 .........(1)
Required Number = (10x+y).
Number obtained on reversing the digits = (10y+x).
Therefore,
(10y+x)−(10x+y)=18
9y−9x=18
y−x=2 ..........(2)
On adding (1) and (2), we get,
2y=14⟹y=7
Therefore,
x=5
Hence, the required number is 57.
Step-by-step explanation:
Hope it is helpful...
Step-by-step explanation:
Let X be the 1st digit and Y be the 2nd digit of the two digit number.
We have X * Y = 12 and (10X + Y) = (10Y + X) + 9.
=> XY = 12 and 9X = 9Y + 9
=> XY = 12 and X = Y + 1
Therefore X = 4 and Y = 3. => Number is 43.
