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How do the graphs of the functions differ from the graph of f(x)=3.5x^3?
For each function, select Steeper, Less steep, or Reflected over the x-axis to describe the differences between the graph of the function and the graph of f(x).
Select all answers that are correct.

How do the graphs of the functions differ from the graph of fx35x3 For each function select Steeper Less steep or Reflected over the xaxis to describe the diffe class=

Respuesta :

Given:

The function is [tex]f(x)=3.5x^3[/tex].

To find:

Whether the given function is Steeper, Less steep, or Reflected over the x-axis to describe the other function.

Solution:

Transformation of function: If f(x) is function and

[tex]g(x)=a\ f(x)[/tex]

Here, a is vertical stretch or compression.

If 0<|a|<1, then g(x) is less steeper than f(x) because f(x) is vertically compressed.

If |a|>1, then g(x) is steeper than f(x) because f(x) is vertically stretched.

If a is negative, the f(x) is reflected over the x-axis, to get g(x).

On comparing the function [tex]p(x)=4.5x^3[/tex] with [tex]f(x)=3.5x^3[/tex], we get 4.5>3.5 So, it is the case vertical stretched and p(x) is steeper than f(x).

On comparing the function [tex]q(x)=-x^3[/tex] with [tex]f(x)=3.5x^3[/tex], we get |-1|=1<3.5 So, it is the case  vertical compression and q(x) is less steeper than f(x) and because of negative sign the function is reflected over axis.

On comparing the function [tex]r(x)=3x^3[/tex] with [tex]f(x)=3.5x^3[/tex], we get 3<3.5 So, it is the case vertical compression and r(x) is less steeper than f(x).

Therefore, [tex]p(x)=4.5x^3[/tex]  is steeper.

[tex]q(x)=-x^3[/tex] is less steep and reflected over the x-axis.

[tex]r(x)=3x^3[/tex] is less steep.