Step-by-step explanation:
[tex] \underline{ \underline{ \text{Solution}}} : [/tex]
[tex] \sf{4x - 3y = 19}[/tex] ••••• equation ( i )
[tex] \sf{2x + 3y = 23}[/tex] ••••• equation ( ii )
The coefficients of y are the same in both equation but the sign of 3y of equation ( i ) differs from the equation ( ii ). So , we add one equation from the other to eliminate 3y.
Adding equation ( i ) and ( ii ) , we get :
[tex] \sf{4x \: \cancel{ - 3y}} = 19[/tex]
[tex] \sf{2x \: \cancel{ \: + 3y}} = 23[/tex]
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[tex] \sf{6x \: \: \: \: \: = \: \: \: 42 }[/tex]
Solve for x :
⟿ [tex] \sf{ \frac{6x}{6} = \frac{42}{6}} [/tex]
⟿ [tex] \boxed{ \sf{x = 7}}[/tex]
Now , substituting the value of x in equation ( ii ) , we get ( Remember : you can substitute the value of x in any of the equation ) :
[tex] \sf{2x + 3y = 23}[/tex]
⟿ [tex] \sf{2 \times 7 + 3y = 23}[/tex]
⟿ [tex] \sf{14 + 3y = 23}[/tex]
⟿ [tex] \sf{3y = 23 - 14}[/tex]
⟿ [tex] \sf{3y = 9}[/tex]
⟿ [tex] \sf{ \frac{3y}{3 } = \frac{9}{3}} [/tex]
⟿ [tex] \boxed{ \sf{y = 3}}[/tex]
[tex] \red{ \boxed{\boxed{ \tt{☥ \: Our \:final \: answer :x = 7 \: and \: y = 3}}}}[/tex]
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✑[tex] \underline{ \underline{ \sf{learn \: more }}}: [/tex]
https://brainly.com/question/20487855?exp=27-1
Hope I helped ! ツ
Have a wonderful day / night ♡
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