how do i answer this please?

Answer:
a) [tex]\sqrt{2}[/tex]
b) [tex]4\sqrt{11}[/tex]
Step-by-step explanation:
a) [tex]6\sqrt{2} - 5\sqrt{2}[/tex]
Taking √2 common ,
[tex]=> \sqrt{2} (6-5)[/tex]
[tex]=> \sqrt{2}[/tex]
b) [tex]\sqrt{11} +3\sqrt{11}[/tex]
Taking √11 common ,
[tex]=> \sqrt{11} (1 +3)[/tex]
[tex]=> 4\sqrt{11}[/tex]