Respuesta :

pialmw

Answer:

part a: root2

part b: 4root11

Answer:

a) [tex]\sqrt{2}[/tex]

b) [tex]4\sqrt{11}[/tex]

Step-by-step explanation:

a) [tex]6\sqrt{2} - 5\sqrt{2}[/tex]

Taking √2 common ,

[tex]=> \sqrt{2} (6-5)[/tex]

[tex]=> \sqrt{2}[/tex]

b) [tex]\sqrt{11} +3\sqrt{11}[/tex]

Taking √11 common ,

[tex]=> \sqrt{11} (1 +3)[/tex]

[tex]=> 4\sqrt{11}[/tex]