Respuesta :
Answer:
The answer is below
Step-by-step explanation:
A football team scored 3 touchdowns, 3 extra points, and 4 field goals.
a. Write an expression to represent the total points the football team scored.
b. Write another expression that is equivalent to the one written above.
c. If each touchdown is worth 6 points, each extra point is 1 point, and each field goal is 3 points, how many total points did the team score?
Solution:
a) Let t represent the number of points for a touchdown, e represent the number of points for the extra point and f represent the number of points for a field goal.
Total points = 3(t) + 3(e) + 4(f) = 3t + 3e + 4f
b) Total points = 3t + 3e + 4f OR
Total points = t + t + t + e + e + e + f + f + f + f OR
Total points = 3(t + e) + 4f
c) Total points = 3(t + e) + 4f = 3(6 + 1) + 4(3) = 3(7) + 4(3)
Total points = 21 + 12 = 33 points
The sum of the points the team has from different point gaining options
give the total number of points the team scores.
- [tex]\underline{\mathrm{The \ total \ points \ the \ football \ team \ scored } = 3 \cdot t + 3 \cdot e + 4 \cdot f}[/tex]
Reasons:
The number of touchdowns by the football team, t = 3
Number of extra points by the football team, e = 3
Number of field goals by the team, f = 4
Therefor, the total number of points, P = 3·t + 3·e +4.f
The specified editor is an equation editor, which can be used to write mathematical equations.
Using an equation editor, we have;
[tex]\mathrm{The \ total \ points \ the \ football \ team \ scored } = 3 \cdot t + 3 \cdot e + 4 \cdot f[/tex]
Learn more about equations here:
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