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The perimeter of ΔABC is 13 cm. It was dilated to create ΔA'B'C'. Point O is the center of dilation. Triangle A B C is dilated to create triangle A prime B prime C prime. The length of O B is 5. The length of B B prime is 15. What is the perimeter of ΔA'B'C'? 13 cm 26 cm 39 cm 52 cm

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MrRoyal

Answer:

39 cm

Step-by-step explanation:

Given

ΔABC and ΔA'B'C'

B = 5 cm

B' = 15 cm

Perimeter ΔABC = 13 cm

Required

Determine the perimeter of ΔA'B'C

[Since ΔABC is dilated to give ΔA'B'C', the first step is to get the scale factor.]

Scale Factor = ΔA'B'C ÷ ΔABC

[Using side B and B' as points of reference]

Scale Factor = B' ÷ B

[Substitute values for B' and B]

Scale Factor = 15 ÷ 5

Scale Factor = 3

[The perimeter of ΔA'B'C' is then calculated as:]

Perimeter ΔA'B'C'= Scale Factor * Perimeter of ΔABC

ΔA'B'C = 3 * 13 cm

ΔA'B'C = 39 cm

Answer: 52 cm

Step-by-step explanation:

EDGU 2021

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