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According to the Center for disease control, 15% of US adults are estimated to have a chronic kidney disease. A random sample of 150 US adults are selected. What is the probability that exactly 35 have chronic kidney disease

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okpalawalter8

Answer:

[tex]P(X=35) =0.2\%[/tex]

Step-by-step explanation:

From the question we are told that

Sample space n = 150

Sample  percentage p = 0.15

Generally people without the disease in the set is give as X

[tex]X= 1-p[/tex]

[tex]X= 0.85[/tex]

35 have kidney disease,

[tex]P(X=35) = C(150,35)*(0.15)^35*(0.85)^115[/tex]

[tex]P(X=35) = 0.0021[/tex]

[tex]P(X=35) =0.2\%[/tex]

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