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A spray can is used until it is empty except for the propellant gas, which has a pressure of 1307 torr at 23°C. If the can is thrown into a fire (T = 477°C), what will be the pressure (in torr) in the hot can

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sebassandin

Answer:

[tex]P_2=3312torr[/tex]

Explanation:

Hello!

In this case, since here we have a pressure-temperature relationship, we need to use the Gay-Lussac's law in order to compute the final pressure as they are in a directly proportional relationship:

[tex]\frac{P_2}{T_2} =\frac{P_1}{T_1}\\\\P_2= \frac{P_1T_2}{T_1}[/tex]

Now, we plug in the given pressure and temperatures in Kelvins to obtain:

[tex]P_2= \frac{1307torr*(477+273)K}{(23+273)K}\\\\P_2=3312torr[/tex]

Best regards!

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